Question

求第七题过程

Answer 1

工作好多年了，有点乱，但结果是对的，仅供参考

Answer 2

TA = TB,∴∠ABT = （180-44）/2 = 68，∵∠CBE = 28，∴∠ABC = 180-68-28 = 84，

∵园中四边形对角互补，∴∠ADC = 180-84 = 96，∵AD = DC，∴∠DAC = ∠DCA = 42， 

∵圆周角相等，∴∠ABD = ∠ACD = 42，

又∵弦切角等于弦的圆周角，∴∠CBE = ∠CAB = 28，

∴△AKB中，∠AKB = 180 - ∠ABD - ∠CAB = 180 - 42 - 28 = 110 。