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x-3y=0 => x=3y.
(2x+y)(x-y)/(x²-2xy+y²)=(2x+y)(x-y)/(x-y)(x-y)=(2x+y)/(x-y)=7y/2y=7/2
(2x+y)(x-y)/(x²-2xy+y²)=(2x+y)(x-y)/(x-y)(x-y)=(2x+y)/(x-y)=7y/2y=7/2
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