Question

C语言数组输入一行字符,分别统计其中每个元音字母（aeiou不分大小写）的个数？

程序运行示例如下：
input a line of character:
Hou old are you?
1 1 0 3 1

Answer 1

已经调试过，麻烦给分

#include "stdio.h"

using namespace std;

char tolower(char c)

{

if (c >= 'A'&& c <= 'Z')

{

c = c + 32;

}

return c;

}

int main()

{

int a, b, c, d, e;

a = b = c = d = e = 0;

char strs[1024];

printf("%s","input a line of character:\r\n");

scanf("%s", strs);

for each (char c in strs)

{

if (tolower(c) == 'a')

{

a++;

}

else if (tolower(c) == 'e')

{

b++;

}

else if (tolower(c) == 'i')

{

c++;

}

else if (tolower(c) == 'o')

{

d++;

}

else if (tolower(c) == 'u')

{

e++;

}

}

printf("%d%d%d%d%d", a, b, c, d, e);

return 0;

}

Answer 2

#include<stdio.h>
#define MAX 5
int main() {
char s[100];
int count[MAX]={0},i,j;
char c[MAX]="aeiou";
printf("input a line of character:\n");

gets(s);/*输入*/
for(i=0;s[i]!='\0';i++)
{
if(s[i]>='A' && s[i]<='Z') s[i]+=32;/*如果为大写则转为小写*/
for(j=0;j<MAX;j++) /*判断是否出现过元音字母*/
{
if(s[i]==c[j]) /*如果出现则数组计数加1，跳出当前循环*/
{
count[j]++;
break;
}
}
}

for(i=0;i<MAX;i++) printf("%d ",count[i]);/*输出结果*/
return 0;
}