Question

电路分析实验题，求过程??题目见图

Answer 1

z总 = R + zC * zL/(zC + zL)
= 1Ω + [j * 0.5Ω * (-j * 1Ω)]/[j * 0.5Ω - j * 1Ω]
= 1Ω + (-j²) * 0.5/(-j * 0.5) Ω
= 1Ω + j * 1Ω
那么，电容两端分压就等于：
Uc = [zC * zL/(zC + zL)]/z总 * U
那么，
I = Uc/zC
= U * [zL/(zC + zL)]/z总
= U * [j * 0.5Ω/(j * 0.5Ω - j * 1Ω)]/(1Ω + j * 1Ω)
= U * (-1)/(1+j)
= U * (-1) * (1-j)/[(1+j)(1-j)]
= U * (j - 1)/(1-j²)
= U * (j - 1)/2
= 5 * (-1 + j)
= 5√2 * [(-√2/2) + j * (√2/2)]
= 5√2 * (cos135° + j * sin135°)
= 5√2 ∠135° (A)