请问这个数学式是怎么转化的?
1个回答
展开全部
lim(x->-1) [1/(x+1) -3/(x^3+1)]
=lim(x->-1) { 1/(x+1) -3/[(x+1)(x^2-x+1)] }
通分母
=lim(x->-1) [(x^2-x+1)-3]/[(x+1)(x^2-x+1)]
=lim(x->-1) (x^2-x-2)/[(x+1)(x^2-x+1)]
=lim(x->-1) (x+1)(x-2)/[(x+1)(x^2-x+1)]
=lim(x->-1) (x-2)/(x^2-x+1)
=-3/3
=-1
=lim(x->-1) { 1/(x+1) -3/[(x+1)(x^2-x+1)] }
通分母
=lim(x->-1) [(x^2-x+1)-3]/[(x+1)(x^2-x+1)]
=lim(x->-1) (x^2-x-2)/[(x+1)(x^2-x+1)]
=lim(x->-1) (x+1)(x-2)/[(x+1)(x^2-x+1)]
=lim(x->-1) (x-2)/(x^2-x+1)
=-3/3
=-1
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