Question

x^2-(p^2+2pq-q^2)x+pq(p+q)(p-q)=0 解方程

亲们帮帮忙，暑假作业啊。。。
想要详解，谢谢啦

Answer 1

x^2-(p^2+2pq-q^2)x+pq(p^2-q^2)=0
x^2-(p^2+2pq-q^2)x+pq(p^2+2pq-q^2)-2p^2q^2=0
x^2-p^2q^2-(p^2+2pq-q^2)(x-pq)-p^2q^2=0
(x-pq)(x+pq-p^2-2pq+q^2)-p^2q^2=0
(x-pq)(x-pq-p^2+q^2)-p^2q^2=0
(x-pq)^2-(p^2-q^2)x-p^2q^2=0
(x-pq-p^2)(x-p^q+q^2)=0
x1=pq+p^2 x2=pq-q^2