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2个回答
展开全部
(xy+1)(x+1)(y+1)+xy
解:原式=(xy+1)(xy+1+x+y)+xy
=(xy+1)(xy+x+1)+y(xy+1)+xy
=(xy+1)(xy+x+1)+y(xy+1+x)
=(xy+x+1)(xy+y+1)
解:原式=(xy+1)(xy+1+x+y)+xy
=(xy+1)(xy+x+1)+y(xy+1)+xy
=(xy+1)(xy+x+1)+y(xy+1+x)
=(xy+x+1)(xy+y+1)
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