Question

解分式方程，如图。求详细过程说明，感谢

Answer 1

具体计算如下图：

Answer 2

练习1

Answer 3

1、(5x-8)/(x²-9) -1 = (3-x)/(x+3)
(5x-8)/[(x-3)（x+3）] = (3-x)/(x+3)+1
(5x-8)/[(x-3)（x+3）] = (3-x+x+3)/(x+3)
(5x-8)/(x-3)=6
5x-8=6(x-3)
移项，化简就得到：
x=10
2、(x+1)/(x-2) = 2x/(x+3) -1
(x+1)/(x-2) = （2x-x-3）/(x+3) =（x-3）/(x+3)
(x+1)(x+3) = （x-3）(x-2)
x²+4x+3=x²-5x+6
化简，得
x=1/3

追问

谢谢

追答

太客气了。能不能加个关注，我是为了百家号收集数量的，平常不会骚扰您的。谢谢！

Answer 4

(1)
(5x-8)/(x^2-9) -1 = (3-x)/(x+3)

(5x-8)/(x^2-9) = (3-x)/(x+3) +1
= 6/(x+3)
(5x-8)/[(x+3)(x-3)]=6/(x+3)
(5x-8)/(x-3)=6 (x≠-3)
5x-8=6(x-3)
=6x-18
x=10
(2)
(x+1)/(x-2) = 2x/(x+3) -1
= (x-3)/(x+3)
(x+1)(x+3)= (x-2)(x-3)
x^2+4x+3=x^2-5x+6
9x=3
x=1/3