小学奥数简便运算题(球过程及答案
1。19941994的二次方-19941992×199419962。2/2×3×4+2/3×4×5+……+2/98×99×1003。(2001+2000×2002/200...
1。19941994的二次方-19941992×19941996
2。2/2×3×4+2/3×4×5+……+2/98×99×100
3。(2001+2000×2002/2001×2002-1)+(2002+2001×2003/2002×2003-1)+(2003+2002×2004/2003×2004-1)
4。1+(1/2)+(1/4)+(1/8)+(1/16)+……+(1/1024)
6.1-(5/6)+(7/12)-(9/20)+(11/30)-(13/42)+(15/56)-(17/72)+(19/90)
7.(12又13/25+7又8/17)×2.5+(9又9/17+10又12/25)×1又1/2
8.1又1/3+2又1/15+3又1/35+4又1/63+……+9又1/323
9。有六个数,其平均数是8又1/2,前四个数的平均数是9又1/4,后三个数的平均数是10,那么第四个数是( )。 展开
2。2/2×3×4+2/3×4×5+……+2/98×99×100
3。(2001+2000×2002/2001×2002-1)+(2002+2001×2003/2002×2003-1)+(2003+2002×2004/2003×2004-1)
4。1+(1/2)+(1/4)+(1/8)+(1/16)+……+(1/1024)
6.1-(5/6)+(7/12)-(9/20)+(11/30)-(13/42)+(15/56)-(17/72)+(19/90)
7.(12又13/25+7又8/17)×2.5+(9又9/17+10又12/25)×1又1/2
8.1又1/3+2又1/15+3又1/35+4又1/63+……+9又1/323
9。有六个数,其平均数是8又1/2,前四个数的平均数是9又1/4,后三个数的平均数是10,那么第四个数是( )。 展开
2个回答
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1.19941994^2-19941992×19941996 (19941994^2为19941994的二次方)
=19941994^2-(19941994-2)(19941994+2)
=19941994^2-(19941994^2-4)
=4
2.
2/2×3×4+2/3×4×5+……+2/98×99×100
=(1/2×3-1/3×4)+(1/3×4-1/4×5)+……+(1/98×99-1/99×100)
=1/2×3-1/99×100
=1649/9900
3.
(2001+2000×2002)/(2001×2002-1)
=(2002-1+2000×2002)/(2001×2002-1)
=(2002+2000×2002-1)/(2001×2002-1)
=(2001×2002-1)/(2001×2002-1)
=1
同理(2002+2001×2003/2002×2003-1)=1
(2003+2002×2004/2003×2004-1)=1;
所以原式=1+1+1=3.
4.
1+(1/2)+(1/4)+(1/8)+(1/16)+……+(1/1024)
=1+(1/2)+(1/4)+(1/8)+(1/16)+……+(1/1024)+(1/1024)-(1/1024)
=1+(1/2)+(1/4)+(1/8)+(1/16)+……+(1/512)-(1/1024)
=1+(1/2)+(1/4)+(1/8)+(1/16)+……+(1/256)-(1/1024)
……
……
=1+(1/2)+(1/2)-(1/1024)
=2-(1/1024)
=2047/1024
6.
1-(5/6)+(7/12)-(9/20)+(11/30)-(13/42)+(15/56)-(17/72)+(19/90)
=1-(1/2+1/3)+(1/3+1/4)-(1/4+1/5)+(1/5+1/6)-(1/6+1/7)+(1/7+1/8)-(1/8+1/9)+(1/9+1/10)
=1-1/2+1/10
=2/5
7.
(12又13/25+7又8/17)×2.5+(9又9/17+10又12/25)×1又1/2
=(12又13/25+7又8/17)×(1又1/2+1)+(9又9/17+10又12/25)×1又1/2
=(12又13/25+7又8/17)×1又1/2+(9又9/17+10又12/25)×1又1/2+(12又13/25+7又8/17)
=1又1/2×(12又13/25+7又8/17+9又9/17+10又12/25)+(12又13/25+7又8/17)
=1又1/2×(23+17)+(12又13/25+7又8/17)
=60+12又13/25+7又8/17
8.
1又1/3+2又1/15+3又1/35+4又1/63+……+9又1/323
=(1+1/3)+(2+1/15)+(3+1/35)+(4+1/63)+……+(9+1/323)
=(1+2+3+4+5+6+7+8+9)+ 1/1×3 +1/3×5+1/5×7+1/7×9+……+1/11×13
=55+1/2×(2/1×3+2/3×5+2/5×7+……+2/11×13)
=55+1/2×(1/1-1/3+1/3-1/5+1/5-1/7+……+1/11-1/13)
=55+1/2×(1-1/13)
=55+6/13=55又6/13
9.
六个数的总和为(8又1/2)×6=51
前四个数之和为(9又1/4)×4=37
后三个数之和为10×3=30
则第四个数为 37+30-51=16.
写得我好累,楼主多加点分吧。
=19941994^2-(19941994-2)(19941994+2)
=19941994^2-(19941994^2-4)
=4
2.
2/2×3×4+2/3×4×5+……+2/98×99×100
=(1/2×3-1/3×4)+(1/3×4-1/4×5)+……+(1/98×99-1/99×100)
=1/2×3-1/99×100
=1649/9900
3.
(2001+2000×2002)/(2001×2002-1)
=(2002-1+2000×2002)/(2001×2002-1)
=(2002+2000×2002-1)/(2001×2002-1)
=(2001×2002-1)/(2001×2002-1)
=1
同理(2002+2001×2003/2002×2003-1)=1
(2003+2002×2004/2003×2004-1)=1;
所以原式=1+1+1=3.
4.
1+(1/2)+(1/4)+(1/8)+(1/16)+……+(1/1024)
=1+(1/2)+(1/4)+(1/8)+(1/16)+……+(1/1024)+(1/1024)-(1/1024)
=1+(1/2)+(1/4)+(1/8)+(1/16)+……+(1/512)-(1/1024)
=1+(1/2)+(1/4)+(1/8)+(1/16)+……+(1/256)-(1/1024)
……
……
=1+(1/2)+(1/2)-(1/1024)
=2-(1/1024)
=2047/1024
6.
1-(5/6)+(7/12)-(9/20)+(11/30)-(13/42)+(15/56)-(17/72)+(19/90)
=1-(1/2+1/3)+(1/3+1/4)-(1/4+1/5)+(1/5+1/6)-(1/6+1/7)+(1/7+1/8)-(1/8+1/9)+(1/9+1/10)
=1-1/2+1/10
=2/5
7.
(12又13/25+7又8/17)×2.5+(9又9/17+10又12/25)×1又1/2
=(12又13/25+7又8/17)×(1又1/2+1)+(9又9/17+10又12/25)×1又1/2
=(12又13/25+7又8/17)×1又1/2+(9又9/17+10又12/25)×1又1/2+(12又13/25+7又8/17)
=1又1/2×(12又13/25+7又8/17+9又9/17+10又12/25)+(12又13/25+7又8/17)
=1又1/2×(23+17)+(12又13/25+7又8/17)
=60+12又13/25+7又8/17
8.
1又1/3+2又1/15+3又1/35+4又1/63+……+9又1/323
=(1+1/3)+(2+1/15)+(3+1/35)+(4+1/63)+……+(9+1/323)
=(1+2+3+4+5+6+7+8+9)+ 1/1×3 +1/3×5+1/5×7+1/7×9+……+1/11×13
=55+1/2×(2/1×3+2/3×5+2/5×7+……+2/11×13)
=55+1/2×(1/1-1/3+1/3-1/5+1/5-1/7+……+1/11-1/13)
=55+1/2×(1-1/13)
=55+6/13=55又6/13
9.
六个数的总和为(8又1/2)×6=51
前四个数之和为(9又1/4)×4=37
后三个数之和为10×3=30
则第四个数为 37+30-51=16.
写得我好累,楼主多加点分吧。
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