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X^ + M^X + N = 0
△=m^4-4n≥0
m^4≥4n
Y^ + 5MY + 7 = 0
△=25m^2-28≥中橘旦0
m^2≥28/25
m<-2/5*√7或m>2/卖扰5√7
x1+x2=-m^2
x1*x2=n
(x1-x2)^2
=(x1+x2)^2-4x1*x2
=(-m^2)^2-4n
=m^4-4n
y1+y2=-5m
y1*y2=7
(y1-y2)^2
=(y1+y2)^2-4y1*y2
=(-5m)^2-28
=25m^2-28
x1-y1=2…………(1)
x2-y2=2…………(2)
(1)+(2),得:
(x1+x2)-(y1+y2)=4
-m^2+5m=4
m^2-5m+4=0
(m-1)(m-4)=0
m=1(舍去)或m=4
由(1),(伍吵2),得:
x1-y1=x2-y2
x1-x2=y1-y2
(x1-x2)^2=(y1-y2)^2
m^4-4n=25m^2-28
256-4n=400-28
4n=-116
n=-29
△=m^4-4n≥0
m^4≥4n
Y^ + 5MY + 7 = 0
△=25m^2-28≥中橘旦0
m^2≥28/25
m<-2/5*√7或m>2/卖扰5√7
x1+x2=-m^2
x1*x2=n
(x1-x2)^2
=(x1+x2)^2-4x1*x2
=(-m^2)^2-4n
=m^4-4n
y1+y2=-5m
y1*y2=7
(y1-y2)^2
=(y1+y2)^2-4y1*y2
=(-5m)^2-28
=25m^2-28
x1-y1=2…………(1)
x2-y2=2…………(2)
(1)+(2),得:
(x1+x2)-(y1+y2)=4
-m^2+5m=4
m^2-5m+4=0
(m-1)(m-4)=0
m=1(舍去)或m=4
由(1),(伍吵2),得:
x1-y1=x2-y2
x1-x2=y1-y2
(x1-x2)^2=(y1-y2)^2
m^4-4n=25m^2-28
256-4n=400-28
4n=-116
n=-29
来自:求助得到的回答
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