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原式=[(√a+1)/(a+√a+1)]*(√a³-1)
=(√a+1)(√a³-1)/(a+√a+1)
=(√a+1)[(√a-1)(a+√a+1)]/(a+√a+1)
=(√a+1)(√a-1)
=a-1
=6
=(√a+1)(√a³-1)/(a+√a+1)
=(√a+1)[(√a-1)(a+√a+1)]/(a+√a+1)
=(√a+1)(√a-1)
=a-1
=6
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