Question

高数积分题一道,设f(x)有连续导数且F(x)=∫(0→x)f(t)f'(2a-t)dt

设f(x)有连续导数且F(x)=∫(0→x)f(t)f'(2a-t)dt，试证：
F(2a)-2F(a)=(f(a))^2-f(0)f(2a).

Answer 1

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追问

你逗我呢？

追答

不好意识，出了点错

Answer 2