Question

java怎么解析[开头的json

怎么用java解析
[{"Title":"济南天气预报","Description":"","PicUrl":"","Url":""},{"Title":"周一(今天, 实时：21℃)\n阴转多云 南风微风 22 ~ 14℃","Description":"","PicUrl":"http://api.map.baidu.com/images/weather/day/yin.png","Url":""},{"Title":"周二\n晴 南风3-4级 24 ~ 14℃","Description":"","PicUrl":"http://api.map.baidu.com/images/weather/day/qing.png","Url":""},{"Title":"周三\n晴转阴 南风3-4级 24 ~ 11℃","Description":"","PicUrl":"http://api.map.baidu.com/images/weather/day/qing.png","Url":""},{"Title":"周四\n多云转晴 北风3-4级 19 ~ 7℃","Description":"","PicUrl":"http://api.map.baidu.com/images/weather/day/duoyun.png","Url":""}]

Answer 1

网上找一下json-lib-2.2.3-xxx.jar，还有一些依赖包
有JSONArray类型的变量，也就是JSON数组，可以把这个字符串转换成json数组
String str=“XXXXXXXX”;
JSONArray oArray=new JSONArray(str);
然后通过这个json数组就可以获得各个部分了

Answer 2

一个{}当成一个对象，一个{}里面的“”：“”当成一个属性的key-value对。然后在java中这样写：
java中用jsonStr接收json类型的对象字符串
Gson gson = new Gson();
List<Map<Strring,String>> JsonList = gson.fromJson(jsonStr,Object.class);
这里一个Map就相当于[]中的一个{};
然后你循环遍历List，和从Map中取值就可以了！

Answer 3

他有专门的json Jar包的。具体你可以看看json官网。www.json.org