如图,高一数学,速度求解,要详细过程,最好能写在纸上照相发过来,谢!
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(1)原式=1/2sin(π/6)=1/4 (2)原式=cosπ/4=根号2/2 (3)原式=1/2*tan(π/6)=根号3/6
(1)原式=(cos^2x+sin^2x)(cos^2x-sin^2x)=cos^2x-sin^2x=cos2x
(2)原式=根号(sin^2x+2sinxcosx+cos^2x)=根号(sinx+cosc)^2=sinx+cosx
(1)右边=(1-(1-2sin^2a))/2=(2sin^2a)/2=sin^2a=左边
(2)右边=(1+(2cos^2a-1))/2=(2cos^2a)/2=cos^2a=左边
(3)sin3a
=sin(a+2a)
=sinacos2a+cosasin2a
=sina(1-2sin^2a)+2cosa*sinacosa
=sina-2sin^3a+2sina(1-sin^2a)
=sina-2sin^3a+2sina-2sin^3a
=3sina-4sin^3a =右边
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1、sin派/6=1/2;cos派/4=√2/2;(1/2)*tan(派/6)=√3/6
2、(cos^2 x-sin^2 x)(cos^2x+sin^2x)=cos2x
√(sinx+cosx)^2=sinx+cosx
3、右边=[1-(1-2sin^2a)]/2=sin^2a=左边
右边=(1+2cos^2a-1)/2=cos^2a=左边
sin3a=sin(2a+a)=sin2acosa+cos2asina
=2sinacos^2a+(1-2sin^2a)sina
=2sina(1-cos^2a)+sina-2sin^3a
=3sina-4sin^3a
2、(cos^2 x-sin^2 x)(cos^2x+sin^2x)=cos2x
√(sinx+cosx)^2=sinx+cosx
3、右边=[1-(1-2sin^2a)]/2=sin^2a=左边
右边=(1+2cos^2a-1)/2=cos^2a=左边
sin3a=sin(2a+a)=sin2acosa+cos2asina
=2sinacos^2a+(1-2sin^2a)sina
=2sina(1-cos^2a)+sina-2sin^3a
=3sina-4sin^3a
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能给详细过程吗?最好能写在纸上发过来
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