(1)(?334)?3?(212)?1+(?12)2(2)[(0.1)-2+(0.01)-1]×(?110)?3(3)(3x-2)-1÷(12x)?2?(3y?12x)
(1)(?334)?3?(212)?1+(?12)2(2)[(0.1)-2+(0.01)-1]×(?110)?3(3)(3x-2)-1÷(12x)?2?(3y?12x)2...
(1)(?334)?3?(212)?1+(?12)2(2)[(0.1)-2+(0.01)-1]×(?110)?3(3)(3x-2)-1÷(12x)?2?(3y?12x)2(4)(a-2-b-2)÷(a-1-b-1)(5)x-2y-2÷(x-2-y-2)(6)(2x-2+y)2-(2x-2-y)2.
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(1)(?3
)?3?(2
)?1+(?
)2
=-
-(
-
)
=-
-
=-
-
=-
;
(2)[(0.1)-2+(0.01)-1]×(?
)?3
=[100+100]×(-1000)
=200×(-1000)
=-200000;
(3)(3x-2)-1÷(
x)?2?(
)2
=
?
?
=
;
(4)(a-2-b-2)÷(a-1-b-1)
=(
-
)÷(
-
)
=
?
3 |
4 |
1 |
2 |
1 |
2 |
=-
64 |
3375 |
2 |
5 |
1 |
4 |
=-
64 |
3375 |
3 |
20 |
=-
256 |
13500 |
2025 |
13500 |
=-
2281 |
13500 |
(2)[(0.1)-2+(0.01)-1]×(?
1 |
10 |
=[100+100]×(-1000)
=200×(-1000)
=-200000;
(3)(3x-2)-1÷(
1 |
2 |
3y?1 |
2x |
=
x2 |
3 |
x2 |
4 |
9 |
4x2y2 |
=
3x2 |
16y2 |
(4)(a-2-b-2)÷(a-1-b-1)
=(
1 |
a2 |
1 |
b2 |
1 |
a |
1 |
b |
=
(b+a)(b?a) |
a2b2 |
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