Question

10到1000中能被11或13整除的和以及被整除的个数用c语言表达

Answer 1

int iNum=0; //能被11或13整除的个数
int iSum=0; //能被11或13整除的和
for (int i=10;i<=1000;i++){
if (i % 11 == 0 || i % 13==0){
iNum++;
iSum +=i;
}
}
//输出iNum,iSum

Answer 2

int iElevenNum = 0;
int iThirteenNum = 0;
int iElevenSum = 0;
int iThirteenSum = 0;
for( int i = 10; i<=1000; i++ )
{
if( i % 11 == 0 )
{
iElevenNum++;
iElevenSum += i;
continue;
}

if( i % 13 == 0 )
{
iThirteenNum++;
iThirteenSum += i;
}
}

int iTotalNum = iElevenNum + iThirteenNum;
int iSum = iElevenSum + iThirteenSum;