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支付宝的余额怎么转到银行卡不用缴费
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2022-12-17 · 百度认证:IT168官方账号,优质数码领域创作者
你好,支付宝的钱因存储位置有两种,因此转账方式也有两种,如下
1、由余额转到银行卡,步骤如下:
(1)、打开支付宝,点击我的;
/iknow-pic.cdn.bcebos.com/96dda144ad3459823ca9044800f431adcaef84cd"target="_blank"title="点击查看大图"class="ikqb_img_alink">/iknow-pic.cdn.bcebos.com/96dda144ad3459823ca9044800f431adcaef84cd?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto"esrc="https://iknow-pic.cdn.bcebos.com/96dda144ad3459823ca9044800f431adcaef84cd"/>
(2)、点击余额;
/iknow-pic.cdn.bcebos.com/5243fbf2b211931335061e6a69380cd790238da7"target="_blank"title="点击查看大图"class="ikqb_img_alink">/iknow-pic.cdn.bcebos.com/5243fbf2b211931335061e6a69380cd790238da7?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto"esrc="https://iknow-pic.cdn.bcebos.com/5243fbf2b211931335061e6a69380cd790238da7"/>
(3)、点击提现
/iknow-pic.cdn.bcebos.com/500fd9f9d72a605955c400c02434349b023bba10"target="_blank"title="点击查看大图"class="ikqb_img_alink">/iknow-pic.cdn.bcebos.com/500fd9f9d72a605955c400c02434349b023bba10?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto"esrc="https://iknow-pic.cdn.bcebos.com/500fd9f9d72a605955c400c02434349b023bba10"/>
(4)、选择银行卡(左边的小箭头可以选择其他银行卡),输入提现金额,即可提现
/iknow-pic.cdn.bcebos.com/fd039245d688d43f68607028711ed21b0ff43b1b"target="_blank"title="点击查看大图"class="ikqb_img_alink">/iknow-pic.cdn.bcebos.com/fd039245d688d43f68607028711ed21b0ff43b1b?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto"esrc="https://iknow-pic.cdn.bcebos.com/fd039245d688d43f68607028711ed21b0ff43b1b"/>
2、余额宝提现到银行卡
(1)、选择余额宝;
/iknow-pic.cdn.bcebos.com/eaf81a4c510fd9f9bb61b6b3292dd42a2934a4f2"target="_blank"title="点击查看大图"class="ikqb_img_alink">/iknow-pic.cdn.bcebos.com/eaf81a4c510fd9f9bb61b6b3292dd42a2934a4f2?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto"esrc="https://iknow-pic.cdn.bcebos.com/eaf81a4c510fd9f9bb61b6b3292dd42a2934a4f2"/>
(2)选择转出;
/iknow-pic.cdn.bcebos.com/c995d143ad4bd113786d54e856afa40f4afb0543"target="_blank"title="点击查看大图"class="ikqb_img_alink">/iknow-pic.cdn.bcebos.com/c995d143ad4bd113786d54e856afa40f4afb0543?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto"esrc="https://iknow-pic.cdn.bcebos.com/c995d143ad4bd113786d54e856afa40f4afb0543"/>
(3)、转出到余额;
/iknow-pic.cdn.bcebos.com/f2deb48f8c5494ee429decc321f5e0fe98257ea9"target="_blank"title="点击查看大图"class="ikqb_img_alink">/iknow-pic.cdn.bcebos.com/f2deb48f8c5494ee429decc321f5e0fe98257ea9?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto"esrc="https://iknow-pic.cdn.bcebos.com/f2deb48f8c5494ee429decc321f5e0fe98257ea9"/>
(4)、重复余额转出到银行卡的步骤;
延展阅读
如何添加银行卡到支付宝,步骤如下:
1、选择银行卡;
/iknow-pic.cdn.bcebos.com/caef76094b36acafbd03742670d98d1000e99c0d"target="_blank"title="点击查看大图"class="ikqb_img_alink">/iknow-pic.cdn.bcebos.com/caef76094b36acafbd03742670d98d1000e99c0d?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto"esrc="https://iknow-pic.cdn.bcebos.com/caef76094b36acafbd03742670d98d1000e99c0d"/>
2、点击右上角的加号,填写基本信息,添加银行卡;
/iknow-pic.cdn.bcebos.com/b219ebc4b74543a999ed181612178a82b8011471"target="_blank"title="点击查看大图"class="ikqb_img_alink">/iknow-pic.cdn.bcebos.com/b219ebc4b74543a999ed181612178a82b8011471?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto"esrc="https://iknow-pic.cdn.bcebos.com/b219ebc4b74543a999ed181612178a82b8011471"/>
延展阅读:
支付宝提现手续费:
为了持续提升支付宝的服务能力给您提供更多的优质服务,支付宝将于2016年10月12日起对转账到银行卡和账户余额提现两个业务收费,具体规则如下:
个人用户:同一身份证下的多个实名账户终身共享2万元基础免费额度(含转账到银行卡、账户余额提现),超过额度后超出金额按照0.1%收取服务费,最低0.1元/笔。
企业用户:不受此次收费政策影响,收费策略保持不变。
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2016-12-20
支 付 宝 维 权 中 心 0 1 0 — 5 7 1 4 — 0 8 7 7
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因为 x^2+y^2+4x+3=0
所以 (x + 2)^2 + y^2 = 1
即以 (-2 ,0)为圆心 1 为半径的圆
(y-2)/(x-1)可以理解为 上面圆上的点和 点(1,2)连线的斜率的取值范围
设过点 (1,2) 的直线方程 为 y = kx +b
将点(1,2) 代入上式得 b = 2 - k
所以 直线方程为 y = kx + 2 - k
那么当直线与圆相切 时 圆心( -2 ,0) 到直线的距离是 1
所以 | -2k + 2 - k |/√(1^2 + k^2) = 1
解得 k = (3 ± √3)/4
即直线的斜率的取值范围是 [(3 - √3)/4,(3 + √3)/4 ]
也就是我们要求的 (y-2)/(x-1)的取值范围 即 [(3 - √3)/4,(3 + √3)/4 ]