
化简 根号[-(x^3)/(x-1)^2]
2个回答
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x/(X-1)根号-x
解:由根号[-(x^3)/(x-1)^2]知,X<0,所以1-X>0,-X>0,根号[-(x^3)/(x-1)^2]=绝对值(X/X-1)根号-x=-x/(1-X)根号-x=x/(X-1)根号-x
解:由根号[-(x^3)/(x-1)^2]知,X<0,所以1-X>0,-X>0,根号[-(x^3)/(x-1)^2]=绝对值(X/X-1)根号-x=-x/(1-X)根号-x=x/(X-1)根号-x
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