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1个回答
展开全部
(x^2+y^2-1)^2-4x^2y^2
=(x^2+y^2-1+2xy)(x^2+y^2-1-2xy)
=[(x+y)^2-1][(x-y)^2-1]
=(x+y+1)(x+y-1)(x-y+1)(x-y-1)
=(x^2+y^2-1+2xy)(x^2+y^2-1-2xy)
=[(x+y)^2-1][(x-y)^2-1]
=(x+y+1)(x+y-1)(x-y+1)(x-y-1)
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