Question

因式分解...

x2+5x+4
x2+10x-11
a2（b-c）-b+c
x4+2x2-3 （设x2为y）
x3-x2+x-1
5ax+5bx+3ay+3by
x2+5y-xy-5x
(2a-b)2+8ab
9x4-36y2
(9x2-2y)2-(1-2y)2
过程啊~~~
给分.

Answer 1

x2+5x+4
x2+10x-11
=(x+11)(x-1)

a2（b-c）-b+c
=a2（b-c）-(b-c)
=(b-c)(a2-1)
=(b-c)(a+1)(a-1)

x4+2x2-3 （设x2为y）
=y^2+2y-3
=(y+3)(y-1)
=(x2+3)(x2-1)
=(x2+3)(x-1)(x+1)

x3-x2+x-1
=x3+x-(x2+1)
=x(x2+1)-(x2+1)
=(x2+1)(x-1)

5ax+5bx+3ay+3by
=5ax+3ay+5bx+3by
=a(5x+3y)+b(5x+3y)
=(5x+3y)(a+b)

x2+5y-xy-5x
=x(x-y)-5(x-y)
=(x-y)(x-5)

(2a-b)2+8ab
=4a2-4ab+b2+8ab
=(2a+b)2

9x4-36y2
=(3x2-6y)(3x2+6y)
=9(x-2y)(x+2y)

(9x2-2y)2-(1-2y)2
=(9x2-2y+1-2y)(9x2-2y-1+2y)
=(9x2-4y+1)(9x2-1)
=(9x2-4y+1)(3x-1) (3x+1)

Answer 2

(x+1)(x+4)
(x-1)(x+11)
(a+1)(a-1)(b-c)
(x+1)(x-1)(x2+3)
(x2+1)(x-1)
(a+b)(5x+3y)
(x-y)(x-5)
(a-1/2)(2b+1)+1/2
2(x2+1)(x+1)(x-1)-2(2y+1)(2y-1)
(9x2-4y+1)(3x+1)(3x-1)

Answer 3

没分数？