如何在java中解压zip和rar文件
2个回答
展开全部
java中有zip包,可以使用
public void getZipFiles(String zipFile, String destFolder) throws IOException {
BufferedOutputStream dest = null;
ZipInputStream zis = new ZipInputStream(
new BufferedInputStream(
new FileInputStream(zipFile)));
ZipEntry entry;
while (( entry = zis.getNextEntry() ) != null) {
System.out.println( "Extracting: " + entry.getName() );
int count;
byte data[] = new byte[BUFFER];
if (entry.isDirectory()) {
new File( destFolder + "/" + entry.getName() ).mkdirs();
continue;
} else {
int di = entry.getName().lastIndexOf( '/' );
if (di != -1) {
new File( destFolder + "/" + entry.getName()
.substring( 0, di ) ).mkdirs();
}
}
FileOutputStream fos = new FileOutputStream( destFolder + "/"
+ entry.getName() );
dest = new BufferedOutputStream( fos );
while (( count = zis.read( data ) ) != -1)
dest.write( data, 0, count );
dest.flush();
dest.close();
}
}
rar的只能用第三方api,比如junrar
public void getZipFiles(String zipFile, String destFolder) throws IOException {
BufferedOutputStream dest = null;
ZipInputStream zis = new ZipInputStream(
new BufferedInputStream(
new FileInputStream(zipFile)));
ZipEntry entry;
while (( entry = zis.getNextEntry() ) != null) {
System.out.println( "Extracting: " + entry.getName() );
int count;
byte data[] = new byte[BUFFER];
if (entry.isDirectory()) {
new File( destFolder + "/" + entry.getName() ).mkdirs();
continue;
} else {
int di = entry.getName().lastIndexOf( '/' );
if (di != -1) {
new File( destFolder + "/" + entry.getName()
.substring( 0, di ) ).mkdirs();
}
}
FileOutputStream fos = new FileOutputStream( destFolder + "/"
+ entry.getName() );
dest = new BufferedOutputStream( fos );
while (( count = zis.read( data ) ) != -1)
dest.write( data, 0, count );
dest.flush();
dest.close();
}
}
rar的只能用第三方api,比如junrar
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询