Question

如何将数据实体转换为 JSON 字符串

Answer 1

Newtonsoft.Json
/// <summary>
/// Json帮助类
/// </summary>
public class JsonHelper
{
/// <summary>
/// 将对象序列化为JSON格式
/// </summary>
/// <param name="o">对象</param>
/// <returns>json字符串</returns>
public static string SerializeObject(object o)
{
string json = JsonConvert.SerializeObject(o);
return json;
}

/// <summary>
/// 解析JSON字符串生成对象实体
/// </summary>
/// <typeparam name="T">对象类型</typeparam>
/// <param name="json">json字符串(eg.{"ID":"112","Name":"石子儿"})</param>
/// <returns>对象实体</returns>
public static T DeserializeJsonToObject<T>(string json) where T : class
{
JsonSerializer serializer = new JsonSerializer();
StringReader sr = new StringReader(json);
object o = serializer.Deserialize(new JsonTextReader(sr), typeof(T));
T t = o as T;
return t;
}

/// <summary>
/// 解析JSON数组生成对象实体集合
/// </summary>
/// <typeparam name="T">对象类型</typeparam>
/// <param name="json">json数组字符串(eg.[{"ID":"112","Name":"石子儿"}])</param>
/// <returns>对象实体集合</returns>
public static List<T> DeserializeJsonToList<T>(string json) where T : class
{
JsonSerializer serializer = new JsonSerializer();
StringReader sr = new StringReader(json);
object o = serializer.Deserialize(new JsonTextReader(sr), typeof(List<T>));
List<T> list = o as List<T>;
return list;
}

/// <summary>
/// 反序列化JSON到给定的匿名对象.
/// </summary>
/// <typeparam name="T">匿名对象类型</typeparam>
/// <param name="json">json字符串</param>
/// <param name="anonymousTypeObject">匿名对象</param>
/// <returns>匿名对象</returns>
public static T DeserializeAnonymousType<T>(string json, T anonymousTypeObject)
{
T t = JsonConvert.DeserializeAnonymousType(json, anonymousTypeObject);
return t;
}
}