Question

数学题，求解答，求详细过程，谢谢！

Answer 1

(1) sin(5π/6)=sin(π-π/6)
=sin(π/6)
=1/2
cos(5π/6)=cos(π-π/6)
=-cos(π/6)
=-√3/2
tan(5π/6)=tan(π-π/6)
=-tan(π/6)
=-√3/3
(2) sin240°=sin(180°+60°)
=-sin60°
=-√3/2
cos240°=cos(180°+60°)
=-cos60°
=-1/2
tan240°=tan(180°+60°)
=tan60°
=√3
(3) sin(-π/6)=-sin(π/6)
=-1/2
cos(-π/6)=cos(π/6)
=√3/2
tan(-π/6)=-tan(π/6)
=-√3/3