Question

350体积（标准状况）的氨溶解在1体积水（密度=1g/m^3）里，求所得氨水（密度=0.924g/m^3）

中NH3的质量分数和物质的量浓度

Answer 1

n(NH3) = 350/22.4 = 15.625mol
m(NH3) = 17*15.625 = 265.625g
m(溶液) = 1000 + 265.625 = 1265.625g
V(溶液) = 1265.625/0.924 = 1370mL = 1.37L

所以NH3质量分数 = 265.625/1265.625 = 21.0%
物质的量浓度 = 15.625/1.37 = 11.4mol/L