Question

3设 y=(1+x^2)/(1-x) 求dy;

Answer 1

y = (1+x²)/(1-x)

y' = [2x(1-x) + (1+x²)]/(1-x)²
y'= (1+2x-x²)/(1-x)²
dy = [(1+2x-x²)/(1-x)²]dx

Answer 2

y = (1+x^2)/(1-x)
y' = [2x(1-x) + (1+x^2)]/(1-x)^2 = (1+2x-x^2)/(1-x)^2
dy = (1+2x-x^2)dx/(1-x)^2