Question

整式乘除法

x的三次方-6x²+11x-6=（x-1）（x²+mx+n）求m，n的值

Answer 1

x^3-6x²+11x-6=x^3-x^2-(5x^2-11x+6)=x^2(x-1)-(5x-6)(x-1)=(x-1)(x^2-5x+6)
m=-5,n=6

Answer 2

右边展开 x立方 +mx方 +nx -x方 -mx -n

m-1=-6 n-m= 11 -n=-6

m =-5 n= 6