Question

帮忙解个方程

3^(2x-1)=4^(3x)
要详细过程谢谢

Answer 1

我了个去了
暑假作业？

两边同时取lg
lg(3^(2x-1))=lg(4^(3x) )
(2x-1)*lg3 = 3x*lg4
2x*lg3 - lg3 = 3x*lg4
(2lg3 - 3lg4)x = lg3
x = lg3/(2lg3 - 3lg4)
x = lg3/(lg(9/64))
x = lg3/lg((3/8)^2)
x = lg3/(2*lg(3/8))
x = 0.5*lg3/lg(3/8)
x = 0.5*log(3/8)3 //以3/8为底，就是3对（3/8）的对数
x = 0.5*log(3)3/log(8)3
x = 0.5*1/log(8)3
x = 0.5*log(3)8

2x-1 = log(3)8-1
3^(2x-1) = 3^(log(3)8-1) = 8/3
3x = 1.5*log(3)8
4^(1.5*log(3)8) =

反正不对了
不知道为什么
你们暑假作业真难