Question

asp ajax url如何传递两个参数？？

function callserver(number_id,good_bad){
var url = “comment_ajax.asp?id=‘+number_id+’&vote_number=”+good_bad;
number_id 与 vote_number 是两个参数
这像不对
把它文本传过去了
并不是一个变量

Answer 1

var url = "comment_ajax.asp?id="+number_id+"&vote_number="+good_bad;
这样就可以了

Answer 2

function callserver(number_id,good_bad){
var url = "comment_ajax.asp?id="+number_id+"&vote_number="+good_bad;
}