Question

C++ map<string, vector< pair<string, string> > > family;输出的问题。

#include <iostream>
#include <utility>
#include <map>
#include <vector>
#include <string>

using namespace std;

int main()
{
map<string, vector< pair<string, string> > > family;
string familyName("wangshifuifeng!");
vector< pair<string, string> > member;
pair<string, string> information;
information = make_pair(familyName,familyName);
member.push_back(information);
family.insert(make_pair(familyName, member));
family.find(familyName);

请问怎么把family的内容输出呀？
// family[familyName].begin().first;
return 0;
}

Answer 1

map<string, vector< pair<string, string> > > family;
for ( map<string, vector< pair<string, string> > >::iterator beg = family.begin();
beg != family.end();
++beg)
{
cout<<beg->first.c_str()<<endl;
for(vector< pair<string, string> >::iterator begvec = beg->second.begin();
begvec != beg->second.end();
++begvec)
{
cout<橘绝<"first:"<<begvec->first.c_str()<<endl;
cout<<"second:"<<begvec->second.c_str()<<endl;
}
}
遍历所有元素，找到你喊锋需要的然后输出就行了。郑伍晌

Answer 2

楼上的说的差不多了，只是循环中加上find条件判断下吧