Question

ansys 命令流问题

cm,rotor1,elem
ALLSEL,ALL
DK,1,,,,0,ux,uy,uz,rotz,
ALLSEL,ALL
DK,6,,,,0,ux,uy,rotz,
ALLSEL,ALL
DK,ALL,,,,0,rotz

f0=5.1e-3
fk,2,fx,f0,0
fk,2,fy,0,-f0
f1=5.1e-3
fk,4,fx,-f1,0
fk,4,fy,0,f1

/SOLU
antype,harmic
dmprat,0.000001
synchro,,rotor1
coriolis,on,,,on
nsubst,200
harfrq,0,200
cmomega,rotor1,,,250
kbc,1
solve
finish

这段代码里面cm,rotor1,elem是什么意思，做谐分析为什么还要定义转速，cmomega,rotor1,,,250是多余的吗，有什么用？

Answer 1

cm是定义组件的命令，将一部分单元定义成一个组件，直接对组件施加边界条件，转速的问题不清楚，没做过之类问题

Answer 2

。。。。不知道啊~~~~~~