道路勘测设计题目,请帮忙解答,如下图,十分感谢!
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q=Ls/2-Ls^3/240R^2=34.99106771m
p=Ls^2/24R=0.510416667m
β0=Ls/2R=0.0875°
T=(R+p) TAN(α/2)+m=98.4256859m
L=(R*α*π)/180°+Ls=195.6637061m
E=(R+p)sec(α/2)-R=5.50282939m
J=2T-L=1.187665649m
ZH=JD-T=K38+450-98.4256859=K38+351.57
HY=ZH+Ls=K38+421.57
QZ= HZ-L/2=K38+449.41
YH=QZ+L/2-Ls=K38+477.24
HZ=YH+Ls=K38+547.24
p=Ls^2/24R=0.510416667m
β0=Ls/2R=0.0875°
T=(R+p) TAN(α/2)+m=98.4256859m
L=(R*α*π)/180°+Ls=195.6637061m
E=(R+p)sec(α/2)-R=5.50282939m
J=2T-L=1.187665649m
ZH=JD-T=K38+450-98.4256859=K38+351.57
HY=ZH+Ls=K38+421.57
QZ= HZ-L/2=K38+449.41
YH=QZ+L/2-Ls=K38+477.24
HZ=YH+Ls=K38+547.24
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