Question

已知p：│1-(x-1)/3│≤2,q:x^2-2x+1-m^2≤0(m>0),且┐p是┐q的必要而不充分条件，求实数m的取值范围

最好有详细过程

Answer 1

x^2-2x+1-m^2≤0(x-1)^2-m^2<=0-m<=x-1<=m1-m=<x<=m+1┐q:x<1-m,x>m+1-2<=1-(x-1)/3≤2-3<=x-1<=9-2<=x<=10┐p:x<-2,x>10┐p是┐q的必要而不充分条件就是说由┐q----->┐p,但┐p推不出┐q所以1-m<-2 m>3，m+1>10 m>9所以m>9