Question

c语言求解，哪位大神帮帮我吧，先谢谢了！





Answer 1

void fun(int a[],int n, int *gt60,int *sum)
{
int i;
int sum1 = 0;
int count =0;
printf("请输入%d个数：",n);
for(i = 0; i < n; i++)
{
scanf("%d",&a[i]);
sum1 = sum1 + a[i];
if(a[i] > 60)
count++;
}
*sum = sum1;
*gt60 = count;

}

fun(arr1,6,>60A,&sumA);
fun(arr2,10,>60B,&sumB);
fun (arr3,15,>60C,&sumC)

追答

#include
#include
void fun(int a[],int n, int *gt60,int *sum)
{
int i;
int sum1 = 0;
int count =0;
printf("请输入%d个数：",n);
for(i = 0; i 60)
count++;
}
*sum = sum1;
*gt60 = count;

}
int main()
{
int arr1[6],arr2[10],arr3[15],gt60A,gt60B,gt60C,sumA,sumB,sumC;
fun(arr1,6,>60A,&sumA);
fun(arr2,10,>60B,&sumB);
fun (arr3,15,>60C,&sumC);
printf("\narr1[0] = %3d,arr1[5] = %3d,sum(arr1) = %d,cnt(arr1) = %d",arr1[0],arr1[5],sumA,gt60A);
printf("\narr2[0] = %3d,arr2[9] = %3d,sum(arr2) = %d,cnt(arr2) = %d",arr2[0],arr2[9],sumB,gt60B);
printf("\narr3[0] = %3d,arr3[14] = %3d,sum(arr3) = %d,cnt(arr3) = %d",arr3[0],arr3[14],sumC,gt60C);
system("PAUSE");
return 0;
}