Question

C++ 遇到 function does not take 1 parameters问题

#include<iostream.h>
#include<iomanip.h>
#include<math.h>
int func1();
int func2();
int main()
{
{
int a,b,l=0;
cout<<"please input two numbers:\n";
cin>>a>>b;
cout<<"primes from"<<a<<"to"<<b<<"is :\n";
func1(a);

}

int func1(int aa)
{
int m;
m=aa;
if (m==2)
return(2);
if( %2==0)
m++;
func2( m);

}

int func2(int n)
{
int sqrtm=sqrtm(n);
int i;
for(i=2;i<=sqrtm;i++)
if(m%i==0)
cout<<endl;
cout<<setw(5)<<m;
}
return 0;
} 啊

还有local function definitions are illegal 是什么意思啊

Answer 1

能改的标了“//****”，只能你自己搞定的标了“//??”或是说明：
#include <iostream>
#include <iomanip>
#include<math.h>
int func1(int); //*********
int func2();
int main()
{
int a,b,l=0; //**************
cout<<"please input two numbers:\n";
cin>>a>>b;
cout<<"primes from"<<a<<"to"<<b<<"is :\n";
func1(a);
return 0;
}
int func1(int aa){
int m;
m=aa;
if (m==2)
return(2);
if( %2==0) //???????
m++;
func2( m);
}
int func2(int n){
int sqrtm=sqrtm(n); //从哪里拿到这个函数sqrtm
int i;
for(i=2;i<=sqrtm;i++)
if(m%i==0) //m从哪里拿到
cout<<endl;
cout<<setw(5)<<m;
}