Question

用字符串的形式输入两个数字，编写函数将两个字符串转换为数值，并输出这两个数和差积商的值,该怎么做？

例1，
输入：
请输入两个数字：
3.5
2.82
输出：
3.5+2.82=6.32
3.5-2.82=0.68
3.5*2.82=9.87
3.5/2.82=1.24113

Answer 1

你这是什么语言做啊。。。。
c++：
#include <iostream>
#include<sstream>

using namespace std;

double getDouble(string str);

void main(){
string str1="",str2="";
double num1 = 0, num2 = 0;
cout<<"输入：\n请输入两个数字：\n";
cin>>str1;
cin>>str2;
num1 = getDouble(str1);
num2 = getDouble(str2);
if(num2 == 0){
cout<<"输出：\n"
<<num1<<"+"<<num2<<"="<<num1+num2<<endl
<<num1<<"-"<<num2<<"="<<num1-num2<<endl
<<num1<<"*"<<num2<<"="<<num1*num2<<endl
<<"0不能为除数";
}else{
cout<<"输出：\n"
<<num1<<"+"<<num2<<"="<<num1+num2<<endl
<<num1<<"-"<<num2<<"="<<num1-num2<<endl
<<num1<<"*"<<num2<<"="<<num1*num2<<endl
<<num1<<"/"<<num2<<"="<<num1/num2<<endl;
}
system("pause");
}

double getDouble(string str){
double d = 0;
stringstream ss;
ss<<str;
if(ss>>d){
return d;
}else{
cout<<"输入错误的参数，结果未知"<<endl;
return 0;
}
}

追问

这个和C语言有什么区别吗

可以用c做吗，大神 求救啊

追答

#include
#include
double getDouble(char ch[]);
void _printf(double num1,double num2);
int main(){
char ch[10] = "";
printf("输入：\n请输入两个数字：\n");
_printf(getDouble(ch),getDouble(ch));
getchar();
return 0;
}

double getDouble(char ch[]){
gets(ch);
double num = 0;
num = atof(ch);
return num;
}
void _printf(double num1,double num2){
if(num2 == 0){
printf("输出：\n%0.2f+%0.2f=%0.2f\n%0.2f-%0.2f=%0.2f\n%0.2f*%0.2f=%0.2f\n0不能为除数",num2,num1,num1+num2,num2,num1,num2-num1,num2,num1,num1*num2);
}else{
printf("输出：\n%0.2f+%0.2f=%0.2f\n%0.2f-%0.2f=%0.2f\n%0.2f*%0.2f=%0.2f\n%0.2f/%0.2f=%0.2f\n",num2,num1,num1+num2,num2,num1,num2-num1,num2,num1,num1*num2,num2,num1,num2/num1);
}
}