Question

如何获取前端传过来的json对象？

function test() {
var dataForm = {
hello : 'world',
hello : 'girls'
};

$.ajax({
type : "POST",
url : 'aaa.do',
data : dataForm,
success : function(msg) {
console.log(msg)
}
})
alert("?");
}
****************************************************************************************
比如说前段封装了这么一个方法，我在后台应该如何去获取到他的对象或者值呢？

Answer 1

获取前端传过来的json对象
代码如下

public JSONObject getRequestContent(HttpServletRequest req) {
JSONObject data = null;
try {
InputStream is = req.getInputStream();
BufferedReader br = new BufferedReader(new InputStreamReader(is, "utf-8"));
String line = null;
StringBuffer content = new StringBuffer();
while ((line = br.readLine()) != null) {
System.out.println(line);
content.append(line);
System.out.println(content);
}
String reqStr = content.toString().trim();
if (StringUtils.isEmpty(reqStr)) {
return new JSONObject();
}
if (reqStr.contains("=")) {
reqStr = reqStr.replaceAll("=", ":");
}
if (!reqStr.startsWith("{")) {
reqStr = "{" + reqStr;
}
if (!reqStr.endsWith("}")) {
reqStr = reqStr + "}";
}
data = JSONObject.fromObject(reqStr);
} catch (Exception e) {
e.printStackTrace();
return new JSONObject();
}
return data;
}

Answer 2

PHP端直接print_r($_POST);返回的就是dataForm数据

追问

我这是JAVA后端

追答

System.out.print()