Question

Linux下两个文件，我想把文件b中第10列（已标出）部分与a第5列（已标出）相同的行输出,怎么操作？

希望最终得到的结果为Pp01 Cufflinks exon 40340 40616 1000 + . gene_id "CUFF.***"; transcript_id "（a和b相同的地方）";





Answer 1

#include<stdio.h>

#define N 256

int main() { char *p,buffer[256],str1[N][20],str[20],str2[20]; FILE *fp; int n,i;

if ( fp=fopen("data1.txt","r") ) {

n=0;

while ( !feof(fp) ) {

fgets(buffer,255,fp);

sscanf(buffer,"%s%s%s%s%s%s%s",str,str,str,str,str1[n],str,str);

n++; if ( n>=N ) break;

}

fclose(fp);

} else printf("Cannot open data1.txt\n");

if ( fp=fopen("data2.txt","r") ) {

while ( !feof(fp) ) {

fgets(buffer,255,fp);

sscanf(buffer,"%s%s%s%s%s%s%s%s%s%s%s%s%s%s", str,str,str,str,str,str,str,str,str,str,str,str2,str,str);

p=str2; while ( *p ) p++; p--; *p=0;

for ( i=0;i<n;i++ ) if ( strcmp(str1[i],str2+1)==0 ) puts(buffer); 

}

fclose(fp);

} else printf("Cannot open data2.txt\n");

return 0;

}

追问

我看不太懂。。。可不可以用awk或者grep做出来呀

追答

你说的不用编程，用grep指令比较？可查此指令用法完成，这里是编程频道