如何在Java Filter 中注入 Service
1个回答
2017-05-01 · 百度知道合伙人官方认证企业
育知同创教育
1【专注:Python+人工智能|Java大数据|HTML5培训】 2【免费提供名师直播课堂、公开课及视频教程】 3【地址:北京市昌平区三旗百汇物美大卖场2层,微信公众号:yuzhitc】
向TA提问
关注
展开全部
在Java Filter 中注入 Service:
解决方法:
public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException { HttpServletRequest req = (HttpServletRequest)request; HttpServletResponse resp = (HttpServletResponse)response; ServletContext sc = req.getSession().getServletContext();
XmlWebApplicationContext cxt = (XmlWebApplicationContext)WebApplicationContextUtils.getWebApplicationContext(sc);
if(cxt != null && cxt.getBean("usersService") != null && usersService == null)
usersService = (UsersService) cxt.getBean("usersService");
Users users = this.usersService.queryByOpenid(openid);
解决方法:
public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException { HttpServletRequest req = (HttpServletRequest)request; HttpServletResponse resp = (HttpServletResponse)response; ServletContext sc = req.getSession().getServletContext();
XmlWebApplicationContext cxt = (XmlWebApplicationContext)WebApplicationContextUtils.getWebApplicationContext(sc);
if(cxt != null && cxt.getBean("usersService") != null && usersService == null)
usersService = (UsersService) cxt.getBean("usersService");
Users users = this.usersService.queryByOpenid(openid);
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询