Question

根号3＋i的6次方

Answer 1

复数z=√3+i
=2(√3/2+1/2i)
=2(cosπ/6+isinπ/6)
即：r=2,θ= π/6
所以：
z^6=r^6(cos6θ+isin6θ)
=64(cosπ+isinπ)
=64(-1+0)
=-64