Question

求下列函数的导数与微分 3.已知e^y + xy - e = y² ,求dy/dx？

Answer 1

直接求导：e^y*y '+y+x*y '=2y*y '
解得 y '=dy/dx=(-y)/(e^y+x-2y) .,2,隐函数求导法则：两边y对x求导得
y'e^y+y+xy'=2yy'
=>y'=-y/(e^y+x-2y)
dy=[-y/(e^y+x-2y)]dx,2,1,