Question

8/3与它的倒数的和去除以6/73,所得的商加上4/5,和是多少?

Answer 1

（8／3＋3／8）÷6／73十4／5
＝（8x8／24十3x3／24）x73／6十4／5
＝（64十9）／24x73／6十4／5
＝73／24x73／6十4／5
＝5329／144十4／5
＝（5x5329十4x144）／144X5
＝（26,645十576）／720
＝27,221／720
＝37又581／720

Answer 2

8/3 + (3/8)^-1 = 8/3 + 3/8 = (83+38)/(3*8) = 11/8
(11/8) / (6/73) + 4/5 = (11/8)(73/6) + (4/5)(73/6) = (1173 + 473)/(8*6) = 851/288
所以和是 851/288