Question

直线AB,CD,EF相交于点O,∠,AOE＝40°,∠BOC=2∠AOC,求∠DOF的度数

Answer 1

∠AOE=40

∠AOB=180

∠AOC=60

∠BOC=120

∠BOF=∠AOE=40

∠BOD=∠AOC=60

∠DOF=∠BOF+∠BOD=100