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(x+2√xy)/(√x+√y)
=(x+2√xy)(√x-√y)/(√x+√y)(√x-√y)
=(x√x-x√y+2x√y-2y√x)/(x-y)
=(x√x+x√y-2y√x)/(x-y)
(1-√2-√3)*(1-√2+√3)
=(1-√2)^2-(√3)^2
=(1-2√2+2)-3
=1-2√2+2-3
=-2√2
=(x+2√xy)(√x-√y)/(√x+√y)(√x-√y)
=(x√x-x√y+2x√y-2y√x)/(x-y)
=(x√x+x√y-2y√x)/(x-y)
(1-√2-√3)*(1-√2+√3)
=(1-√2)^2-(√3)^2
=(1-2√2+2)-3
=1-2√2+2-3
=-2√2
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