Question

怎样用Java语言随机产生n（n由键盘输入）个1－1000之间的整数；

Answer 1

public class ScannerDemo{
    public static void main(String[] args){
        java.util.Scanner sc = new java.util.Scanner(System.in);
        System.out.println("请输入，只能为数字");
        try{
            int[] arr = new int[sc.nextInt()];
            for(int i = 0; i < arr.length; i++){
                arr[i] = (new java.util.Random().nextInt(1000)+1);
            }
            System.out.println(java.util.Arrays.toString(arr));
        }catch(Exception e){
            System.err.println("输入有误!");
        }
    }
}

Answer 2

Random rand = new Random();
int i = rand.nextInt(); //int范围类的随机数
i = rand.nextInt(1000); //生成0-1000以内的随机数

Answer 3

import java.util.Random;
import java.util.Scanner;

public class Test {

public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
Random random = new Random();
System.out.print("输入 N: ");
int n = scanner.nextInt();
for (int i = 0; i < n; i++) {
System.out.println((i + 1) + " -> " + random.nextInt(1000));
}
}
}