求值:[2sin50°+sin10°(1+√3tan10°)]×√2sin80°
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楼主你好![2sin50°+sin10°(1+√3tan10°)]√(2sin80°)
= [2sin50 + sin10(cos10+√3sin10)/cos10]√2sin80
= [2sin50cos10+2sin10(cos60cos10+sin60sin10)√2sin80/cos10
= 2[sin50cos10 + sin10cos(60-10)]√2
= 2sin(50+10)√2
= √6
望采纳!
= [2sin50 + sin10(cos10+√3sin10)/cos10]√2sin80
= [2sin50cos10+2sin10(cos60cos10+sin60sin10)√2sin80/cos10
= 2[sin50cos10 + sin10cos(60-10)]√2
= 2sin(50+10)√2
= √6
望采纳!
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