Question

C++ MFC中 截取特定字符串

比如一串字符串 01 00 00 88 02 00 00 88 03 00 00 88 04 00 00 88

截取88前的字符串 变成 01 00 00 ，02 00 00 .......

Answer 1

//#include "stdafx.h"//vc++6.0加上这一行.
#include <iostream>
#include <string>
using namespace std;
int main(void){
string stra("01 00 00 88 02 00 00 88 03 00 00 88 04 00 00 88"),strb;
for(int ln=stra.length(),i=0;i<ln;i++)
if(stra[i]!='8' || stra[i+1]!='8')
strb+=stra[i];
else{
strb+=',';
i++;
}
cout << strb << endl;
return 0;
}

Answer 2

用Find 得到index
根据index 用substring（好像是mid打头的函数）

Answer 3

#include <iostream>
#include <string>
using namespace std;
int main(void)
{
string name("01 00 00 88 02 00 00 88 03 00 00 88 04 00 00 88");
int startpos = 0;

while (-1!= startpos )
{
startpos = name.find('88'); //找到'88'的位置
if( startpos != -1 )
{
name.replace(startpos,2,",");
}
}
cout << name << endl;
system("pause");
return 0;
}