Question

python读取脚本所在目录文件名，放到aa.txt文件中，然后读取aa.txt文件的每

python读取脚本所在目录文件名，放到aa.txt文件中，然后读取aa.txt文件的每一行，一行作为一个文件名，并打开，现在打开总是报错invalid argument:'bb.txt\n'
代码如下
import os
path = os.getcwd()
for filename in os.listdir(path):
f = open('aa.txt','a')
f = write(filename)
f = write("\n")
f.close
f = open('aa.txt')
line = f.readline()
while line:
inFile = line
if inFile:
filehandle = open(inFile)
line = f.readline()
f.close()
filehandle.close()

Answer 1

import os
path = os.getcwd()
f = open('aa.txt','a')
for filename in os.listdir(path):
    fullname=os.path.join(path,filename)
    if os.path.isfile(fullname):
        f.write(fullname)
        f.write("\n")
f.close()
f = open('aa.txt')
for line in f:
    infile=line.rstrip('\n')
    filehandle=open(infile)
    filehandle.close()
f.close()