Question

求tan(-75度)的三角函数值

Answer 1

tan(-75度)
=-tan75°
=-tan(45º+30º)
=-(tan45º+tan30º)/(1-tan45ºtan30º)
=-(1+√3/3)/(1-√3/3)
=-(√3+1)/(√3-1)
=-(3+1+2√3)/(3-1)
=-2-√3