计算1.5^(-1/3)*(-7/6)^0+8^0.25*开四次方根号2+(开3次方根号2*√3)^6- √（-2/3）^2/3
1个回答
展开全部
解:
原式
=(3/2)^(-1/3)*1+8^(1/4)*2^(1/4)+[2^(1/3)*√3]^6-(2/3)^(1/3)
=[(3/2)^(-1）]^(1/3)+8^(1/4)*2^(1/4)+[2^(1/3)*√3]^6-(2/3)^(1/3)
=(2/3)^(1/3)+16^(1/4)+4*27-(2/3)^(1/3)
=0+2+108
=110
谢谢
原式
=(3/2)^(-1/3)*1+8^(1/4)*2^(1/4)+[2^(1/3)*√3]^6-(2/3)^(1/3)
=[(3/2)^(-1）]^(1/3)+8^(1/4)*2^(1/4)+[2^(1/3)*√3]^6-(2/3)^(1/3)
=(2/3)^(1/3)+16^(1/4)+4*27-(2/3)^(1/3)
=0+2+108
=110
谢谢
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
