(tan^2x)/(1+tan^2x)+cos^4x+sin^2xcos^2x的化简过程 谢了,要快哦
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(tan^2x)/(1+tan^2x)+cos^4x+sin^2xcos^2x
=(tan^2x)/sec^2x+cos^4x+sin^2xcos^2x
=(tan^2x)*cos^2x+cos^4x+sin^2xcos^2x
=sin^2x+cos^4x+sin^2xcos^2x
=sin^2x+cos^2x(sin^2x+cos^2x)
=sin^2x+cos^2x
=1
=(tan^2x)/sec^2x+cos^4x+sin^2xcos^2x
=(tan^2x)*cos^2x+cos^4x+sin^2xcos^2x
=sin^2x+cos^4x+sin^2xcos^2x
=sin^2x+cos^2x(sin^2x+cos^2x)
=sin^2x+cos^2x
=1
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